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Catacatalina4
a fost răspuns

x∈[tex][0; 2 \pi )[/tex] , a,b ∈ R , 0<a<b , tg x=2ab/ a patrat minus b patrat. E= a sin x -b cosx.

Răspuns :

Sergiutaranu
a*sinx-b*cosx, impartim expresia la cosx, obtinem a*tgx-b, tgx=2ab/a^2-b^2, deci:
2a^2b/a^2-b^2 -b=  2a^2b-a^2b-b^3/a^2-b^2= a^2b-b^3/a^2-b^2= b(a^2-b^2)/ a^2-b^2= b.
Raspuns: E(x)= b.

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