[tex](2\frac{3}{8}+3\frac{7}{24}):(4\frac{2}{3}-1\frac{1}{8})=\\ \\=(\frac{8*2+3}{8}+\frac{3*4+2}{24}):(\frac{3*4+2}{3}-\frac{8*1+1}{8})\\\\=(\frac{19}{8}+\frac{14}{24}):(\frac{14}{3}-\frac{9}{8})\\\\=(\frac{57+14}{24}):(\frac{112-27}{24})\\\\=\frac{71}{24}*\frac{24}{85}\\ \\=\frac{71}{85}[/tex]
