100a+10b+c+100a+10c+b=1165
200a+11b+11c=1165
Valoarea maxima a lui a,b,c este 9.
daca 200a+11•9+11•9=1165
200a+99+99=1165
200a+198=1165
200a=967
=> a=5, pentru ca b,c<9
5•200+11b+11c=1165
1000+11(b+c)=1165
11(b+c)=165
b+c=15
=> (b,c)={(6,9),(7,8),(8,7),(9,6)}
abc= {569, 578, 587, 596}
