(x+1)/2-3/(y+1)=4 | * 2(y+1)
(x+1)(y+1)-6=8(y+1)
(x+1)(y+1)=8(y+1)+6
x+1=(8(y+1)+6)/(y+1)
x=(8(y+1)+6)/(y+1) - 1
x=(8y+8+6)/(y+1) - (y+1)/(y+1)
x=(8y+14-y-1)/(y+1)
x=(7y+13)/(y+1)
x=(7(y+1)+6)/(y+1)
(y+1) | 7(y+1) => (y+1) | 6 => y+1 ∈{ 1 ,2 ,3, 6 } => y∈{0,1,2,5}
y=0=> x= (7y+13)/(y+1)=> x= 13/1=13
y=1=> x= (7y+13)/(y+1)=> 20/2=10
y=2=> x= 27/3=9
y=5=> x=48/6=8
(y,x)∈{(0,13);(1,10);(2,9);(5,8)}
