Răspuns:
A___________B
|
|
D___________C
BD^2 = AB^2 + AD^2 (t.Pitagora)
BD^2 = 64 + 16 = 80 =>BD=4rad5
t.cat. : AD^2 = DM•DB (M € DB, AM_|_DB)
16=DM•4rad5 =>DM=16/4rad5 =>DM=4rad5/5
=>MB=4rad5 - 4rad5/5=16rad5/5
t.h. : AM^2 = DM•MB = 4rad5/5 • 16rad5/5=64/5
=>AM=8rad5/5
