Masa camion: M=4t=4000kg
Masa incarcatura: mo=2t=2000kg
Masa totala: m=M+mo=6000kg
Greutate totala: G=m g=60000N
Lungimea pantei: d=12km=12000m
Diferenta de nivel: h=200m
sin(α) = h / d = 200 / 12000 = 2 / 120 = 1/60
a) Forta de tractiune: Ft - G sin(α) - Ff = m a
Daca urcarea are loc cu viteza constanta, acceleratia este 0.
Ft = G sin(α) + Ff = 60000 * 1 / 60 + 1520 = 1000 + 1520 = 2520N
Ft=2520N
b) Lucrul mecanic total: Lt = Ft * d = 2520 * 12000 = 30240 * 10³J
Lt = 30.24 MJ
c) Puterea motorului: P = Ft * v
v = 36km/h = 10m/s
P = 2520 * 10 = 25.2 kW
