a) In ΔADB cu m(D)=90°
AD patrat = AB patrat - BD patrat
AD= 169-25
AD=√144
AD=12
AΔABC= b•h/2=10•12/2=120/2=60 cm
b) In ΔBDA cu m(D)=90°
AD patrar =BA patrat - AD patrat
AD=225-81
AD=√144
AD=12
AΔABC =b•h/2=18•12/2= se simplifica 18 cu 2 =108/2=54 cm