Răspuns:
Explicație pas cu pas:
[tex]a) P(x) = 2x^3 + 3x^2 + 4x + 6 = (2x+3)(x^2+2)=0\\2x+3 = 0 => 2x = -3 => x_1 = -\frac{3}{2} \\x^2 + 2 = 0 =>x^2 = -2 =2i^2 => x_2 = \sqrt{2}i, x_3 = -\sqrt{2}i\\\\b) P(x) = x^3 - 2x^2 - 9x + 18\\P(x) = (x-2)(x+3)(x-3) = 0\\x- 2 = 0 => x_1 = 2\\x+ 3 = 0=> x_2 = -3\\x - 3 = 0 => x_3 = 3[/tex]
