A = [(3^3 × 3^4 + 3^6 × 3 + 3^2012 : 3^2005) × (27^3)^55]^4 + 1^2012 =
={(3^7 + 3^7 + 3^7) × [(3^3)^3]^55}^4 + 1 =
= [3×3^7 × (3^9)^55]^4 + 1 =
= (3^8 × 3^495)^4 + 1 =
= (3^503)^4 + 1 =
= 3^2012 + 1
Răspuns:
Explicație pas cu pas:
A=[(3^7+3^7+3^7)×(3^9)^55]^4+1==(3^8×3^495]^4+1=(3^503)^4+1=
=3^2012+1