[tex]\sf
Faci~Pitagora~ca~sa~vezi~daca~triunghiul~este~dreptunghic: \\ \\
3^2+(3 \sqrt{3})^2=6^2 \\ \\
9+27=36 (adevarat) \longrightarrow \triangle~este~dreptunghic. \\ \\
Faci~sinusul~unghiului~opus~laturii~de~3 \sqrt{3}: \\ \\
sin= \frac{\not 3 \sqrt{3}}{^2\not 6}= \frac{ \sqrt{3}}{2} \longrightarrow \boxed{\sf \measuredangle 1=60^o} \\ \\
\boxed{\sf \measuredangle2=90^o} \\ \\
\measuredangle3=180-90-60 \\ \\
\boxed{\sf \measureangle3=30^o}[/tex]
