x + y/2 + z/3 + t/4 = 1/8
Avem si 1/x = 2/y = 3/z = 4/t = k
x = 1/k
2/y=k -> y/2=1/k
3/z=k -> z/3=1/k
4/t=k -> t/4=1/k
Inlocuind in prima ecuatie, gasim: 1/k + 1/k + 1/k + 1/k = 1/8
4/k = 1/8
k = 32
Deci: x=1/32
y = 2/32 = 1/16
z=3/32
t=4/32 = 1/8
