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(n+3)! / (n+2)(n+3) < 1000
aflati n


Răspuns :

Răspuns:

[tex] \frac{(n + 3)! }{(n + 2)(n + 3)} < 1000 \\ \frac{(n + 1)! (n + 2)(n + 3)}{(n + 2)(n + 3)} < 1000 \\ (n + 1)! < 1000 \\ 6! < 1000 \\ 1 \times 2 \times 3 \times 4 \times 5 \times 6 < 1000 [/tex]

n={0,1,2,3,4,5}