Răspuns :
[tex]\it a)\ 5^2+2^4-0^3+2^0=25+16-0+1=42\\ \\ b)\ 3^2-2^3+4^3-2^2=27-8+64-4=79\\ \\ c)\ (2^2\cdot3^2-5^2):11=(4\cdot9-25):11 =11:11=1\\ \\ d)\ 3^{21}:(3^4)^5+(5^2)^2:5^{7^0}=3^{21}:3^{20}+5^4:5^1=3+5^3=3+125=128[/tex]
[tex]\it e)\ (5600-4\cdot5^2):2^2\cdot5-2012^0=5500:4\cdot5-1=1375\cdot5-1=6874[/tex]