Răspuns:
a) [tex]\frac{2^{8}+2^{6}}{35*64} = \frac{2^{6}(2^{2}+1)}{35*2^{6}} =\frac{4+1}{35} =\frac{5}{35} =\frac{1}{7}[/tex]
b) [tex]\frac{3^{9}-3^{6} }{3^{6}*35} =\frac{3^{6}(3^{3}-1) }{3^{6}*35}=\frac{27-1}{35} =\frac{26}{35}[/tex]
c) [tex]\frac{5*3^{8}+3^{10}}{3^{8}*35} = \frac{3^{8}(5+3^{2})}{3^{8}*35} = \frac{5+9}{35} = \frac{14}{35} =\frac{2}{5}[/tex]
Explicație pas cu pas: