2,3 g md g
2Na + Cl2 --> 2NaCl
2x23 2x58,5
=> md = 2,3x2x58,5/2x23
= 5,85 g NaCl
stim ca c% = mdx100/ms
si ms = md + m.apa
= 5,85 + m.apa
=> 15% = 5,85x100/(5,85+m.apa)
=> m.apa = 33,15 g
facem proba
md = 5,85 g , ms = 33,15+5,85 = 39 g
=> c% = 5,85x100/39 = 15%