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1.Calculatii:a)(radical12)la puterea 0=
(1 supra0,2)la puterea -1=
(-1)la puterea12=
0 la puterea 12=
d)(radical2)la puterea a8a=
(-1supra radical 3)la puterea 6=
(1 supra radical 7) la puterea -4=
(-radical2supra3) la puterea -6=

Răspuns :

Renatemambouko
a(√12)⁰=1
(1 /0,2)⁻¹=(5)⁻¹=1/5
(-1)¹²=1
0¹²=0
d)(√2)⁸=2⁴=16
(-1√3)⁶= (-√3/3)⁶=(3/9)³=(1/3)³=1/27
(1/√7)⁻⁴=[1/(1/√7)]⁴=(√7)⁴=49
(-√2/3)⁻⁶=(-3/√2)⁶=(-3√2/2)⁶=729x8/64=729/8

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