Răspuns :
Răspuns:
CnH2n-2 prin ardere produce nCO2+ (n-1)H2O
niu,apa= 108g/18g/mol= 6mol]
niu,alchina- 120/(14n-2)
1mol alchina............(n-1)mol apa
120/(14n-2)................6
6(14n-2)=120(n-1)------> n=3----> propina \
CH≡C-CH3+H2-->CH2=CH-CH3
CH2=CH-CH3+H2---> CH2=3-CH2-CH3
CH≡CH-CH3+Cl2---> CHCl=CHCl-CH3
CHCL=CHCL-CH3+Cl2---> CHCl2-CHCL2-CH3
CH≡C-CH3 + HCL---->CH2=CCL-CH3
CH2-CCL-CH3+HCL----> CH3-CCL2-CH3
CH≡C-CH3+HOH---> [CH2=COH-CH3]-⇄ CH3-C-CH3
II
O
CH≡C-CH3+Ag[(NH3)2]OH----> CAg≡C-CH3+2NH3+H2O
Explicație: