Răspuns:
Este b raspunsul final
Aria= AB× AC× sin 45°/2=
[tex] \frac{12 \times 8 \times \frac{ \sqrt{2} }{2} }{2} = 12 \times 4 \times \frac{ \sqrt{2} }{2} = 24 \sqrt{2} cm {}^{2} [/tex]
