Răspuns :
(2x-3)^2-x(3x - 10) -(x-1)^2=
4x^2-12x+9-3x^2+10x-(x^2-2x+1)=
4x^2-12x+9-3x^2+10x-x^2+2x-1=
0-12x+9+10x+2x-1=
0+0+9-1=
8
(2x-3)^2-x(3x - 10) -(x-1)^2=
4x^2-12x+9-3x^2+10x-(x^2-2x+1)=
4x^2-12x+9-3x^2+10x-x^2+2x-1=
0-12x+9+10x+2x-1=
0+0+9-1=
8