Răspuns:[tex](\sqrt{2}-3)^{2}=\\\sqrt{2^{2} }-2*\sqrt{2}*3+3^{2}=\\\sqrt{4}-6\sqrt{2} +9=\\2-6\sqrt{2} +9[/tex]
am aplicat formula de calcul prescurtat [tex](a+b)^{2}[/tex]
