Răspuns:
M,Na2SO4=(2X23gNa +32gS+4X16gNa)/mol-=142g
a. 142g sare.........64gO
X.....................32g x= 32x142x64g Na2SO4=.........CALCULEAZA !!!!
b.1mol atomi..........6,023X10²³tomi----> deci, 1mol atomi Na
1mol Sare........142g..............2mol atomiNa
x,..................1mol atomi
x= 71g
c. 142kg sare...........32kgS
x..............................6,4kg S
X= 142x6,4/142 Kg=.............................calculeaza !!!!
d 142g sare..............2x23gNa
x......................................11,5g
x= 11,5x142/46g=..........................calculeaza !!!!!
Explicație:
