maaa putetiii ajutaaaa

7. {a,b} i.p. {3,2}
[tex] = > \frac{3}{a} = \frac{2}{b} = k = > a = \frac{3}{k} \: b = \frac{2}{k} [/tex]
a-b=17
[tex] = > \frac{3}{k} - \frac{2}{k} = 17 = > \frac{1}{k} = 17 = > k = 17 = >
a = \frac{3}{17} \: b = \frac{2}{17} [/tex]
8. {a,b} i.p. {6,5}
=> 6/a=5/b=k
=>a=6/k b=5/k
4a-b=24/k-5/k= 21k
2a+3b=12/k+15/k= 27k
4a-b/2a+3b= 21k/27k = 7/9