Răspuns:
a=(3[tex]\sqrt{3}[/tex]+2[tex]\sqrt{2}[/tex][tex]\sqrt{35-\sqrt{864} }[/tex]
[([tex]5\sqrt{2}) ^{2}[/tex]-49)=
=[tex](3\sqrt{3}+2\sqrt{2} )[/tex]([tex]\sqrt{} \frac{35+\sqrt{1225-861} }{2} - \sqrt{} \frac{35-\sqrt{1225-861} }{2}[/tex]) + 50-49=
=[tex](3\sqrt{3}+2\sqrt{2} )[tex](\sqrt{\frac{35+\sqrt{361} }{2} } - \sqrt{\frac{35-\sqrt{361} }{2} } )[/tex]+1=
=[tex](3\sqrt{3}+2\sqrt{2} )([tex]\sqrt{} \frac{35+19}{2} - \sqrt{} \frac{35-19}{2}[/tex])+1=
=[tex](3\sqrt{3}+2\sqrt{2} )([tex]\sqrt{27} -\sqrt{8}[/tex])+1=
=[tex](3\sqrt{3}+2\sqrt{2} )[tex](3\sqrt{3}-2\sqrt{2} )+1=(27-8)+1=20
Explicație pas cu pas:
