Explicație pas cu pas:
(x+3)³-x-3=(x+3)³-1(x+3)=(x+3)[(x+3)²-1]=(x+3)(x+3-1)(x+3+1)=
(x+3)(x+2)(x+4)
Răspuns:
(x+3)^3-x-3=
= (x+3)^3-1(x+3)=
= (x+3)·[(x+3)^2-1]
avem a^2-b^2=(a+b)(a-b)
= (x+3)·(x+3+1)(x+3-1)=
=(x+3)(x+4)(x+2)=
=(x+2)(x+3)(x+4)
