Explicație pas cu pas:
(3x+7)/(2x+1)€Z <=>2x+1|3x+7
2x+1|3x+7=>2x+1|6x+14
2x+1|2x+1=>2x+1|6x+3
Le scadem:
2x+1|6x+14-6x-3=>2x+1|11=>2x+1€D11 in Z =>
2x+1€{-11,-1,1,11} =>
2x€{-12,-2,0,10} =>
x€{-6,-1,0,5}
Cum x€Z => x€{-6,-1,0,5} solutie
