Răspuns:
a) (2x-3)(3x+2)-6([tex]x^{2}[/tex]-x+3)=6[tex]x^{2}[/tex]+4x-9x-6-6[tex]x^{2}[/tex]+6x-18=x-24
b)2x(x-3)-3(x²-x+4)-5x=2x²+6x-3x²+3x-12-5x=-x²-8x-12=-(x²+4x+4+4x*8)=
=-[(x+2)²+4(x+2)]=-(x+2)(x+2+4)=-(x+2)(x+6)
c) (3x+2)(2x-3)-3(x-2)(2x-3)+4x-5=6x²-9x+4x-12-3(2x²-3x-4x+6)+4x-5=
=6x²-5x-12-6x²+21x-18+4x-5=20x-35=5(4x-7)
Explicație pas cu pas:
