Răspuns:
Explicație pas cu pas:
b) (x-2)²=36i² unde i²=-1
(x-2)²-36i²=0 x-2+6i=0 x1=2-6i
x-2-6i=0 x2=2+6i
c) (x-3)²-16i²=0 x-3+4i=0 x1=3-4i
x-3-4i=0 x2=3+4i
d) 4x²-81i²=0 2x-9i=0 x1=9i/2
2x+9i=0 x2=-9i/2
e) (z-2)²+(2z-3)²=0 (z-2)²-(2z-3)²i²=0
z-2-2zi+3i=0 z(1-2i)=2-3i z1=(2-3i/(1-2i)
z-2+2zi-3i=0 z(1+2i)=2+3i z2=(2+3i)/(1+2i(
