Răspuns:
Explicație:
-se afla masa pura de fier
p=88% [ 100-12=88 ]
mp=p.mi :100
mp=88 . 190,90 : 100=167, 992 g Fe pur
167,992 g yg xg
2 Fe + 3Cl2 =2 FeCl 3
2.56g 3.71g 2.162,5g
x=167,992. 2 . 162,52: 112=487,47 gFeCl3
y=167,992 . 213 : 112=319,48 g clor
n=319,48 g: 71g/moli=4,49 moli Cl2
MFeCl3=56 + 3.35,5=162,5--->162,5g/moli
Verifica calculele !!!!!