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Alyna2001
a fost răspuns

Descompuneti in factori: a) x²+9x+14
b)x²+10x+21
c)x²+6x+5
d)x²-10x+14
e)x²-12x+35
f)x²-5x+4

Răspuns :

Renatemambouko
a) x²+9x+14=(x+7)(x+2)
b)x²+10x+21=(x+7)(x+3)
c)x²+6x+5=(x+5)(x+1)
d)x²-10x+14=[x-(5-√11)][x-(5+√11)]
e)x²-12x+35=(x-5)(x-7)
f)x²-5x+4=(x-1)(x-4)

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