[tex]\left[2^0+2^1+3^{14}:\left(3\times 13^{12}\right)\right]^{12}:3^2=\\ \\ =\left(2^0+2^1+3^{14}:13^{13}\right)^{12}:3^2\\ \\ = \left(2^0+2^1+3\right)^{12}:3^2\\ \\ = \left(1+2+3\right)^{12}:3^2\\ \\ =6^{12}:3^2\\ \\ = 2^{12}\cdot 3^{12}:3^2\\ \\ =2^{12}\cdot 3^{10}\\\\ =2^2\cdot (2\cdot 3)^{10}\\ \\ = 4\cdot 6^{10}[/tex]
