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Daryka
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[(3^2)^6*3^5/3^15+2^0*2*2^2]*2-2^5

Răspuns :

Needhelp112

[(3^2)^6 * 3^5/3^15 + 2^0 * 2 * 2^2] * 2 - 2^5 =

= (3^12 * 3^5/3^15 + 1 * 2^3) * 2 - 2^5 =

= (3^17/3^15 + 2^3) * 2 - 2^5 =

= (3^2 + 2^3) * 2 - 2^5 =

= (9 + 8) * 2 - 32 =

= 17 * 2 - 32 =

= 34 - 32 =

= 2

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