Răspuns :
a+b+c=579
b=3a
c=b+12; c=3a+12
a+3a+3a+12=579
7a=567
a=81
b=3a=3*81=243
c=b+12=243+12=255
b=3a
c=b+12; c=3a+12
a+3a+3a+12=579
7a=567
a=81
b=3a=3*81=243
c=b+12=243+12=255
primul nr |----------|
al II-lea |----------|----------|----------| } 579
al III-lea nr |----------|----------|----------|-12--|
1. Aflam primul nr.
(579-12):7=567:7=81
2. Aflam al II-lea nr.
81x3= 243
3. Aflam al III-lea nr.
243+12=255
al II-lea |----------|----------|----------| } 579
al III-lea nr |----------|----------|----------|-12--|
1. Aflam primul nr.
(579-12):7=567:7=81
2. Aflam al II-lea nr.
81x3= 243
3. Aflam al III-lea nr.
243+12=255