Răspuns :
Răspuns:
x/3 a strabatut in prima zi
x-x/3=(3x-x)/3=2x/3 rest
2x/3·2/5+2=4x/15+2 a strabatut a2a zi
x/3+4x/15+2+3=x aducem la acelasi numitor comun
5x+4x+30+45=15x
75=15x-9x
x=75:6=>x=12,5 km lungimea drumului
|______|____________| prima zi (t/3)
|____|_| a doua zi (2/5 + 2km) din 2t/3
|______| a treia zi (3 km)
3/5 = 5 km => 1/5 = 5/3 km
5/5 = 25/3 km
25/3 = 2t/3
6t = 75
t = 75/6
t = 12,5 km