Explicație pas cu pas:
n=V(2+4+6+...+48+25)=> n=V2(1+2+3+.....+24)+25=>
n=V(2*24*25/2+25) => n=V(24*25+25) =>n=V25(24+1) =>
n=V25²=|25|=25
n=|V3-3|+V(7-4V3)-V(2V3-4)²
n=3-V3+V(4-4V3+3)-|2V3-4|
n=3-V3+V(2-V3)²-(4-2V3)
n=3-V3+|2-V3|-4+2V3 =>
n=3-V3+2-V3-4+2V3 => n=1
n=|x+3|+V(x-1)²+|-7|
-3<=x<=1 => 0<=x+3 si x-1<=0
=>n=x+3+|x-1|+7 =>
n=x+3+1-x+7 => n=11
