Răspuns:
a)AOB+BOC+COD+AOD=360°
AOB=x
BOC=2x°+10°
COD=3x°-5°
AOD=4x°+5°
x+2x+10+3x-5+4x+5=360
10x+10=360
10x=350
x=35=AOB
BOC=2×35+10=80
COD=3×35-5=105-5=100
AOD=4×35+5=140+5=145.
b)BOC:2=80:2=40
COD:2=100:2=50
unghiul format de bisectoare=40+50=90.
Sper ca te am ajutat!:)