Răspuns:
b.6x^4+6x^3+x^3+-3x^2-3x+1=
6x^3(x+1)+x^3+1-3x^(x+1)=
6x^3(x+1)+(x+1)(x^2-x+1)-3x^2(x+1)=
(x+1)(6x^3+x^2-x+1-3x^2)=
(x+1)(6x^3-2x^2-x+1)
a.x³-5x²-x+21=0
x³-3x²-2x²+18+x-3
x²(x-3)-2(x^2-9)+(x-3)
(x^2(x-3)-2((x-3)(x+3)+(x-3)=
(x-3)(x^2-2x+6+1)
Explicație pas cu pas:
