a)
2² x 3 x 5 = 60
Divizorii lui 60 sunt :
1, 2, 3, 5, 60
Acum facem combinatii intre factorii primi :
2² = 4, 2x3 = 6, 2x5 = 10, 2²x3 = 12, 3x5 = 15, 2²x5 = 20, 2x3x5 = 30
D₁₂ = {1 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60}
b)
3² x 5² = 225
Divizorii lui 225 sunt :
1, 3, 5, 225
Acum facem combinatii intre factorii primi :
3² = 9, 3x5 = 15, 5² = 25, 3²x5 = 45, 3x5² = 75
D₂₂₅ = {1, 3, 5, 9, 15, 25, 45, 75, 225}
c)
210 = 2 x 3 x 5 x 7
Divizorii lui 210 sunt :
1, 2, 3, 5, 7, 210
Acum facem combinatii intre factorii primi :
2x3 = 6, 2x5 = 10, 2x7 = 14, 3x5 = 15, 3x7 = 21, 5x7 = 35,
2x3x5 = 30, 2x3x7 = 42, 2x5x7 = 70, 3x5x7 = 105
D₂₁₀ = {1, 2, 3, 5, 6, 7, 10, 14, 15, 21, 30, 35, 42, 70, 105, 210}