Răspuns :
[tex]a= \sqrt98+ \sqrt32- \sqrt50
b= \sqrt162+ \sqrt18- \sqrt72[/tex]
[tex]Ma= \frac{ \sqrt{98}+ \sqrt{32}+ \sqrt{50}+ \sqrt{162}+ \sqrt{18}- \sqrt{72} }{2} [/tex]
Ma=[tex] \frac{7 \sqrt{2}+4 \sqrt{2}-5 \sqrt{2}+9 \sqrt{2}+3 \sqrt{2}-6 \sqrt{2} }{2} [/tex]
Ma=[tex] \frac{12 \sqrt{2} }{2} =6 \sqrt{2} [/tex]
Mg=[tex] \sqrt{(7 \sqrt{2}+4 \sqrt{4}-5 \sqrt{2})(9 \sqrt{2}+3 \sqrt{2}-6 \sqrt{2})= \sqrt{6 \sqrt{2}*6 \sqrt{6} } } [/tex]
Mg=[tex]6 \sqrt{2} [/tex]
b= \sqrt162+ \sqrt18- \sqrt72[/tex]
[tex]Ma= \frac{ \sqrt{98}+ \sqrt{32}+ \sqrt{50}+ \sqrt{162}+ \sqrt{18}- \sqrt{72} }{2} [/tex]
Ma=[tex] \frac{7 \sqrt{2}+4 \sqrt{2}-5 \sqrt{2}+9 \sqrt{2}+3 \sqrt{2}-6 \sqrt{2} }{2} [/tex]
Ma=[tex] \frac{12 \sqrt{2} }{2} =6 \sqrt{2} [/tex]
Mg=[tex] \sqrt{(7 \sqrt{2}+4 \sqrt{4}-5 \sqrt{2})(9 \sqrt{2}+3 \sqrt{2}-6 \sqrt{2})= \sqrt{6 \sqrt{2}*6 \sqrt{6} } } [/tex]
Mg=[tex]6 \sqrt{2} [/tex]