Răspuns :
In Δ ABA' aplicam pitagora⇒AA'²+AB²=A'B²
AA'²=26²-10²
AA'=675-100
AA'=√576
AA'=24
Suma muchiilor= 6x muchia bazei+ 3x muchia laterala=
6x10+3x24=60+72=132cm
In Δ ABA' aplicam pitagora⇒AA'²+AB²=A'B²
AA'²=26²-10²
AA'=675-100
AA'=√576
AA'=24
Suma muchiilor= 6x muchia bazei+ 3x muchia laterala=
6x10+3x24=60+72=132cm