Răspuns :
a : 4 = 3 rest 0
a = 3 × 4 + 0
a = 12 + 0
a = 12
b : 4 = 3 rest 1
b = 3 × 4 + 1
b = 12 + 1
b = 13
c : 4 = 3 rest 2
c = 3 × 4 + 2
c = 12 + 2
c = 14
d : 4 = 3 rest 3
d = 3 × 4 + 3
d = 12 + 3
d = 15
12 + 13 + 14 + 15 =
25 + 14 + 15 =
39 + 15 = 54 => suma numerelor
n : 4 = 3 + rest
impartitorul 4 => restul poate fi 0, 1, 2 sau 3
n = 3x4 + {0, 1, 2, 3}
n = 12 + {0, 1, 2, 3}
n = 12, 13, 14, 15
S = 12 + 13 + 14 + 15
S = 54