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Dacă a+b=12 si b+c=15,calculati
3×[110-(2a+2b)+5b+5c]=​

Răspuns :

Needhelp112

3×[110-(2a+2b)+5b+5c] = 3×[110-2(a+b)+5(b+c)] = 3×(110-2×12+5×15) = 3×(110-24+75) = 3×161 = 483

Boredaf

3×[110-(2a+2b)+5b+5c]=

3×(110-2×12+5×15)=

3×(110-24+75)=

3×161=

483