Răspuns:
M,Al(OH)3=78g/mol
M,KOH= 56g/mol
3X56g....................................78g
3KOH + Al(NO3)3 ------> Al(OH)3 +3 KNO3
28g..............................................x
x=mAl(OH)3= 28x78/3x56g=...........................calculeaza
Explicație:
