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a fost răspuns

1. 2^8 : (-2)^6 - (-5)^0 =

2. 2 - (-3)^4 * 3^5 : (-3)^7=



3. 3 (x^2 - 2x -2) + x(6-3x) =


4. 2x +7 = x-2 , x apartine Z

5. 3(t+1)-2 = 16 , t apartine R

6.11 - 3 (x-2) = 14 x apartine R

Ajutati-ma va rog , dau coroana ! ​

Răspuns :

BiancaCh765

1. 2^8:2^6-1=

2^8-6-1=

2^4-1=

4-1=

3

2. 2-(-3)^4* 3^5: (-3)^7=

2+3^4* 3^5: (-3)^7=

2+3^4+5-7=

2+3^2=

2+9=

11

3. 3(x^2-2x-2)+x(6-3x)=

3x^2-3*2x-3*2+6x-3x^2=

3x^2-6x-6+6x-3x^2=

3x^2-3x^2=0

-6x+6x=0

=> =-6

4. 2x+7=x-2,x∈ Z

2x-x=-2-7

x=-9

-9∈ Z

5. 3(t+1)-2=16,t∈ R

3t+3*1-2=16

3t+3-2=16

3t+1=16

3t=16-1

3t=15

t=15:3

t=5

5∈ R

6. 11-3(x-2)=14x,x∈ R

11-3x+3*2=14x

11-3x+6=14x

11+6=17

=>17-3x=14x

-3x-14x=-17

-17x=-17

x=-17:(-17)

x=1

1∈ R

sper ca te-am ajutat :))

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