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Va rog ma ajutati cu un exercitiu la mate :D E(x)=x-1 supra 5x la puterea 3.si F(x)=x+1 supra 5x la puterea 3. Calculati :a) E(x)+F(X)
b) F(x)-E(x)
c) E(x) · F(x)
d) E(x) ÷ F(x)
e) (F(X)) ²

Răspuns :

Enashraluk
a). [tex] \frac{x-1}{ 125*x^{3} } + \frac{x+1}{125*x^{3} } = \frac{x-1+x+1}{125*x^{3} } = \frac{2x}{125*x^{3} } = \frac{2}{125* x^{2} } [/tex]

b) [tex] \frac{x+1}{125* x^{3} } - \frac{x-1}{125* x^{3} } = \frac{x+1-x+1}{125* x^{3} } = \frac{2}{125* x^{3} } [/tex]

c) [tex] \frac{x-1}{125* x^{3} } * \frac{x+1}{125* x^{3} } = \frac{(x-1)*(x+1)}{15625* x^{6} } = \frac{ x^{2}-1 }{15625* x^{6} } [/tex]

d). [tex] \frac{x-1}{125* x^{3} } * \frac{125* x^{3} }{x+1} = \frac{x-1}{x+1} [/tex]

e). [tex] \frac{x+1}{125* x^{3} } * \frac{x+1}{125* x^{3} } = \frac{ x^{2} +2x+1}{15625* x^{6} } [/tex]

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