Răspuns :
Intr-un paralelogram diag se injmatatesc
notezi BO=x
inlocuiesti in raport
x/2x+√9/4
1/2+3/2=4/2=2
notezi BO=x
inlocuiesti in raport
x/2x+√9/4
1/2+3/2=4/2=2
BO/BD=1/2 DEOARECE O ESTE MIJLOCUL CELOR DOUA DIAGONALE
BO/BD+9/4=1/2+RADICALDIN(9/4)=1/2+3/2=4/2=2
BO/BD+9/4=1/2+RADICALDIN(9/4)=1/2+3/2=4/2=2