Răspuns:
R1: 2CH4---> C2H2+3H2
R2: CH4---> C+ 2H2
in R1: 48mol 24mol 72mol
CH4-------> C2H2 + 3H2
in R2: 39mol.....................(150-72)mol
CH4---------> C +2H2
TOTAL MOLI CH4: 48+39= 87mol
Cu= niu(r1) x100/ niu,total= 48x100/160=30%
C t=niu(r1+r2)x100/niu,total= 87x100/160=54,4%
Explicație: