Stim ca ma≥mg
(1+a1)/2≥√(1•a1)
(1+a2)/2≥√(1•a2)
(1+a3)/2≥√(1•a3)
...........................
(1+an)/2≥√(1•an)
(1+a1) (1+a2) (1+a3)...... (1+an)/ 2^n≥√(a1•a2•a3•....•an)
a1•a2•a3•....•an=1
=>(1+a1) (1+a2) (1+a3)...... (1+an)≥[tex]2^{n}[/tex]
