Răspuns:
Explicație:
CaC2 +2H2O----> CH≡CH+Ca(OH)2
acetilena
CH≡CH+ HOH-----> [CH2=CHOH]⇄CH3-CHO
alcool vinilic acetaldehida
CH3-CHO + O------> CH3-COOH acid acetic
CH≡CH + CH3COOH----> CH2=CH-
I
OCOCH3 acetat de vinil
n CH2=CH-OCOCH3----> [-CH2-CH-]
I
OCOCH3 ]n poliacetat de vinil
C4H6O2
mC:mH:mO= 4X12: 6X1 : 2X16
= 24: 3: 16
M,poliacetat de vinil= 86kg/kmol
nXM,monomer= M,polimer---> n=1000
m,carbid pur p=m-x100/mi----> mp= 400x80/100kg=320kg
din reactiile scrise, rezulta; 2mol carbid..............1mol polimer
2x64kg................................86000kg
320kg...........................x
x=m=215000kg
