Răspuns:
x≤16
x=1,2,3,...,16
A={1,2,3,...,16}
x³≤64
x³≤4³
x≤4
B={1,2,3,4}
A∩B={1,2,3,..,16}∩{1,2,3,4}={1,2,3,4}
AUB={1,2,3,4,...,16}U{1,2,3,4}={1,2,3,4,...,16}
A\B={5,6,7,...,16}
B\A={1,2,3,4}\{1,2,3,4,...,16}=Ф
Explicație pas cu pas:
