Vμ₀=22,41 l=0,02241 m³
Na=6,023*10²³ molecule/moli
a) μ_NO=m_N+m_O=14+16=30 g/moli=0,03 kg/moli
b) N=Na*υ
υ=m/μ
N=Na*υ=Na*m/μ=6,023*10²³*2/0,03=4*10²⁵ molecule
c)μ=Na*m₀=>m₀=μ/Na=0,03/6,023*10²³=5*10⁻²⁶ kg
υ=d³=Vμ₀/Na=>d=∛Vμ₀/Na=∛0,02241/6,023*10²³=3,33*10⁻⁹ m
